B(x)=5x^2+16x+3

Solution for B(x)=5x^2+16x+3 equation:

(B)=5B^2+16B+3

We move all terms to the left:

(B)-(5B^2+16B+3)=0

We get rid of parentheses

-5B^2+B-16B-3=0

We add all the numbers together, and all the variables

-5B^2-15B-3=0

a = -5; b = -15; c = -3;
Δ = b2-4ac
Δ = -152-4·(-5)·(-3)
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{165}}{2*-5}=\frac{15-\sqrt{165}}{-10}
$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{165}}{2*-5}=\frac{15+\sqrt{165}}{-10}
$